(3x)(4x+1)+7X=

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Solution for (3x)(4x+1)+7X= equation:


Simplifying
(3x)(4x + 1) + 7X = 0

Remove parenthesis around (3x)
3x(4x + 1) + 7X = 0

Reorder the terms:
3x(1 + 4x) + 7X = 0
(1 * 3x + 4x * 3x) + 7X = 0
(3x + 12x2) + 7X = 0

Reorder the terms:
7X + 3x + 12x2 = 0

Solving
7X + 3x + 12x2 = 0

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-3x' to each side of the equation.
7X + 3x + -3x + 12x2 = 0 + -3x

Combine like terms: 3x + -3x = 0
7X + 0 + 12x2 = 0 + -3x
7X + 12x2 = 0 + -3x
Remove the zero:
7X + 12x2 = -3x

Add '-12x2' to each side of the equation.
7X + 12x2 + -12x2 = -3x + -12x2

Combine like terms: 12x2 + -12x2 = 0
7X + 0 = -3x + -12x2
7X = -3x + -12x2

Divide each side by '7'.
X = -0.4285714286x + -1.714285714x2

Simplifying
X = -0.4285714286x + -1.714285714x2

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