(3x)(x)(1.5x)=48

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Solution for (3x)(x)(1.5x)=48 equation:



(3x)(x)(1.5x)=48
We move all terms to the left:
(3x)(x)(1.5x)-(48)=0
We add all the numbers together, and all the variables
3xx(+1.5x)-48=0
We multiply parentheses
3x^2-48=0
a = 3; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·3·(-48)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*3}=\frac{-24}{6} =-4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*3}=\frac{24}{6} =4 $

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