(3x)(x)-36=(3x-2)(x-2)

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Solution for (3x)(x)-36=(3x-2)(x-2) equation: 



(3x)(x)-36=(3x-2)(x-2)

We move all terms to the left:

(3x)(x)-36-((3x-2)(x-2))=0

We multiply parentheses ..

-((+3x^2-6x-2x+4))+3xx-36=0



We calculate terms in parentheses: -((+3x^2-6x-2x+4)), so:

(+3x^2-6x-2x+4)

We get rid of parentheses

3x^2-6x-2x+4

We add all the numbers together, and all the variables

3x^2-8x+4

Back to the equation:

-(3x^2-8x+4)



We get rid of parentheses

-3x^2+8x+3xx-4-36=0

We add all the numbers together, and all the variables

-3x^2+8x+3xx-40=0

We move all terms containing x to the left, all other terms to the right

-3x^2+8x+3xx=40

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