(3x)(x+10)+x=180

Solution for (3x)(x+10)+x=180 equation:

(3x)(x+10)+x=180

We move all terms to the left:

(3x)(x+10)+x-(180)=0

We add all the numbers together, and all the variables

x+3x(x+10)-180=0

We multiply parentheses

3x^2+x+30x-180=0

We add all the numbers together, and all the variables

3x^2+31x-180=0

a = 3; b = 31; c = -180;
Δ = b2-4ac
Δ = 312-4·3·(-180)
Δ = 3121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{3121}}{2*3}=\frac{-31-\sqrt{3121}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{3121}}{2*3}=\frac{-31+\sqrt{3121}}{6}
$