(3x)+(10x+15)=50

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Solution for (3x)+(10x+15)=50 equation: 



(3x)+(10x+15)=50

We move all terms to the left:

(3x)+(10x+15)-(50)=0

We get rid of parentheses

3x+10x+15-50=0

We add all the numbers together, and all the variables

13x-35=0

We move all terms containing x to the left, all other terms to the right

13x=35

x=35/13

x=2+9/13

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