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(3x)+(14/5x)=(31/5)
We move all terms to the left:
(3x)+(14/5x)-((31/5))=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x+(+14/5x)-((+31/5))=0
We get rid of parentheses
3x+14/5x-((+31/5))=0
We calculate fractions
3x+()/25x^2+(-((+31*5x)/25x^2=0
We multiply all the terms by the denominator
3x*25x^2+(-((+31*5x)+()=0
We calculate terms in parentheses: +(-((+31*5x)+(), so:Wy multiply elements
-((+31*5x)+(
75x^3+(-((+31*5x)+()=0
We calculate terms in parentheses: +(-((+31*5x)+(), so:We do not support expression: x^3
-((+31*5x)+(
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