(3x)+(2x)=108

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Solution for (3x)+(2x)=108 equation: 



(3x)+(2x)=108

We move all terms to the left:

(3x)+(2x)-(108)=0

We add all the numbers together, and all the variables

5x-108=0

We move all terms containing x to the left, all other terms to the right

5x=108

x=108/5

x=21+3/5

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