(3x)+(2x)=108

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Solution for (3x)+(2x)=108 equation:



(3x)+(2x)=108
We move all terms to the left:
(3x)+(2x)-(108)=0
We add all the numbers together, and all the variables
5x-108=0
We move all terms containing x to the left, all other terms to the right
5x=108
x=108/5
x=21+3/5

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