(3x)+(2x+40)+(4x)+(x+50)=360

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Solution for (3x)+(2x+40)+(4x)+(x+50)=360 equation: 



(3x)+(2x+40)+(4x)+(x+50)=360

We move all terms to the left:

(3x)+(2x+40)+(4x)+(x+50)-(360)=0

We add all the numbers together, and all the variables

7x+(2x+40)+(x+50)-360=0

We get rid of parentheses

7x+2x+x+40+50-360=0

We add all the numbers together, and all the variables

10x-270=0

We move all terms containing x to the left, all other terms to the right

10x=270

x=270/10

x=27

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