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(3x)+(2x+40)+(4x)+(x+50)=360
We move all terms to the left:
(3x)+(2x+40)+(4x)+(x+50)-(360)=0
We add all the numbers together, and all the variables
7x+(2x+40)+(x+50)-360=0
We get rid of parentheses
7x+2x+x+40+50-360=0
We add all the numbers together, and all the variables
10x-270=0
We move all terms containing x to the left, all other terms to the right
10x=270
x=270/10
x=27
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