(3x)+(2x-25)+(4x-11)+(x+6=)360

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Solution for (3x)+(2x-25)+(4x-11)+(x+6=)360 equation:



(3x)+(2x-25)+(4x-11)+(x+6=)360
We move all terms to the left:
(3x)+(2x-25)+(4x-11)+(x+6-()360)=0
We get rid of parentheses
3x+2x+4x+(x+6-()360)-25-11=0
We calculate terms in parentheses: +(x+6-()360), so:
x+6-()360
We add all the numbers together, and all the variables
x
Back to the equation:
+(x)
We add all the numbers together, and all the variables
10x-36=0
We move all terms containing x to the left, all other terms to the right
10x=36
x=36/10
x=3+3/5

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