(3x)+(3x)+(2x-10)+(2x-10)=360

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Solution for (3x)+(3x)+(2x-10)+(2x-10)=360 equation: 



(3x)+(3x)+(2x-10)+(2x-10)=360

We move all terms to the left:

(3x)+(3x)+(2x-10)+(2x-10)-(360)=0

We add all the numbers together, and all the variables

6x+(2x-10)+(2x-10)-360=0

We get rid of parentheses

6x+2x+2x-10-10-360=0

We add all the numbers together, and all the variables

10x-380=0

We move all terms containing x to the left, all other terms to the right

10x=380

x=380/10

x=38

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