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(3x)+(4x)=(x+90)
We move all terms to the left:
(3x)+(4x)-((x+90))=0
We add all the numbers together, and all the variables
7x-((x+90))=0
We calculate terms in parentheses: -((x+90)), so:We get rid of parentheses
(x+90)
We get rid of parentheses
x+90
Back to the equation:
-(x+90)
7x-x-90=0
We add all the numbers together, and all the variables
6x-90=0
We move all terms containing x to the left, all other terms to the right
6x=90
x=90/6
x=15
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