(3x)+(4x+3)=(10x-9)

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Solution for (3x)+(4x+3)=(10x-9) equation: 



(3x)+(4x+3)=(10x-9)

We move all terms to the left:

(3x)+(4x+3)-((10x-9))=0

We get rid of parentheses

3x+4x-((10x-9))+3=0



We calculate terms in parentheses: -((10x-9)), so:

(10x-9)

We get rid of parentheses

10x-9

Back to the equation:

-(10x-9)



We add all the numbers together, and all the variables

7x-(10x-9)+3=0

We get rid of parentheses

7x-10x+9+3=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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