(3x)+(5/3x)=90

Solution for (3x)+(5/3x)=90 equation:

(3x)+(5/3x)=90

We move all terms to the left:

(3x)+(5/3x)-(90)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3x+(+5/3x)-90=0

We get rid of parentheses

3x+5/3x-90=0

We multiply all the terms by the denominator


3x*3x-90*3x+5=0

Wy multiply elements

9x^2-270x+5=0

a = 9; b = -270; c = +5;
Δ = b2-4ac
Δ = -2702-4·9·5
Δ = 72720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72720}=\sqrt{144*505}=\sqrt{144}*\sqrt{505}=12\sqrt{505}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-270)-12\sqrt{505}}{2*9}=\frac{270-12\sqrt{505}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-270)+12\sqrt{505}}{2*9}=\frac{270+12\sqrt{505}}{18}
$