(3x)+(6x+16)=2(10x-47)

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Solution for (3x)+(6x+16)=2(10x-47) equation: 



(3x)+(6x+16)=2(10x-47)

We move all terms to the left:

(3x)+(6x+16)-(2(10x-47))=0

We get rid of parentheses

3x+6x-(2(10x-47))+16=0



We calculate terms in parentheses: -(2(10x-47)), so:

2(10x-47)

We multiply parentheses

20x-94

Back to the equation:

-(20x-94)



We add all the numbers together, and all the variables

9x-(20x-94)+16=0

We get rid of parentheses

9x-20x+94+16=0

We add all the numbers together, and all the variables

-11x+110=0

We move all terms containing x to the left, all other terms to the right

-11x=-110

x=-110/-11

x=+10

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