(3x)+(x-28)+2(x+5)=180

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Solution for (3x)+(x-28)+2(x+5)=180 equation: 



(3x)+(x-28)+2(x+5)=180

We move all terms to the left:

(3x)+(x-28)+2(x+5)-(180)=0

We multiply parentheses

3x+(x-28)+2x+10-180=0

We get rid of parentheses

3x+x+2x-28+10-180=0

We add all the numbers together, and all the variables

6x-198=0

We move all terms containing x to the left, all other terms to the right

6x=198

x=198/6

x=33

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