(3x)/(x+2)-(9)/(x-4)=3

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Solution for (3x)/(x+2)-(9)/(x-4)=3 equation:


D( x )

x+2 = 0

x-4 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:-2) U (-2:4) U (4:+oo)

(3*x)/(x+2)-(9/(x-4)) = 3 // - 3

(3*x)/(x+2)-(9/(x-4))-3 = 0

(3*x)/(x+2)-9*(x-4)^-1-3 = 0

(3*x)/(x+2)-9/(x-4)-3 = 0

(3*x*(x-4))/((x+2)*(x-4))+(-9*(x+2))/((x+2)*(x-4))+(-3*(x+2)*(x-4))/((x+2)*(x-4)) = 0

3*x*(x-4)-9*(x+2)-3*(x+2)*(x-4) = 0

3*x^2-3*x^2-21*x+6*x-18+24 = 0

6-15*x = 0

(6-15*x)/((x+2)*(x-4)) = 0

(6-15*x)/((x+2)*(x-4)) = 0 // * (x+2)*(x-4)

6-15*x = 0

6-15*x = 0 // - 6

-15*x = -6 // : -15

x = -6/(-15)

x = 2/5

x = 2/5

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