(3x)/3-(x-2)/2=(x+5)/7

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Solution for (3x)/3-(x-2)/2=(x+5)/7 equation: 


x in (-oo:+oo)

(3*x)/3-((x-2)/2) = (x+5)/7 // - (x+5)/7

(3*x)/3-((x-2)/2)-((x+5)/7) = 0

(-1*(x-2))/2+(-1*(x+5))/7+x = 0

(-1*7*(x-2))/(2*7)+(-1*2*(x+5))/(2*7)+(2*7*x)/(2*7) = 0

2*7*x-1*7*(x-2)-1*2*(x+5) = 0

14*x-9*x+4 = 0

5*x+4 = 0

(5*x+4)/(2*7) = 0

(5*x+4)/(2*7) = 0 // * 2*7

5*x+4 = 0

5*x+4 = 0 // - 4

5*x = -4 // : 5

x = -4/5

x = -4/5

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