(3x)/4=(5x-1)/3+4

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Solution for (3x)/4=(5x-1)/3+4 equation: 



(3x)/4=(5x-1)/3+4

We move all terms to the left:

(3x)/4-((5x-1)/3+4)=0

We calculate fractions


9x/()+(-((5x-1)*4)/()=0



We calculate terms in parentheses: +(-((5x-1)*4)/(), so:

-((5x-1)*4)/(

We multiply all the terms by the denominator


-((5x-1)*4)



We calculate terms in parentheses: -((5x-1)*4), so:

(5x-1)*4

We multiply parentheses

20x-4

Back to the equation:

-(20x-4)



We get rid of parentheses

-20x+4

Back to the equation:

+(-20x+4)



We get rid of parentheses

9x/()-20x+4=0

We multiply all the terms by the denominator


9x-20x*()+4*()=0

We add all the numbers together, and all the variables

9x-20x*()=0

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