(3x)2-10=564x=

Solution for (3x)2-10=564x= equation:

(3x)2-10=564x=

We move all terms to the left:

(3x)2-10-(564x)=0

We add all the numbers together, and all the variables

3x^2-564x-10=0

a = 3; b = -564; c = -10;
Δ = b2-4ac
Δ = -5642-4·3·(-10)
Δ = 318216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{318216}=\sqrt{4*79554}=\sqrt{4}*\sqrt{79554}=2\sqrt{79554}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-564)-2\sqrt{79554}}{2*3}=\frac{564-2\sqrt{79554}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-564)+2\sqrt{79554}}{2*3}=\frac{564+2\sqrt{79554}}{6}
$