(3x)2=-10x-5

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Solution for (3x)2=-10x-5 equation:



(3x)2=-10x-5
We move all terms to the left:
(3x)2-(-10x-5)=0
We add all the numbers together, and all the variables
3x^2-(-10x-5)=0
We get rid of parentheses
3x^2+10x+5=0
a = 3; b = 10; c = +5;
Δ = b2-4ac
Δ = 102-4·3·5
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{10}}{2*3}=\frac{-10-2\sqrt{10}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{10}}{2*3}=\frac{-10+2\sqrt{10}}{6} $

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