(3x)x2=4x+20

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Solution for (3x)x2=4x+20 equation: 



(3x)x2=4x+20

We move all terms to the left:

(3x)x2-(4x+20)=0

We get rid of parentheses

3xx2-4x-20=0

We add all the numbers together, and all the variables

-4x+3xx2-20=0

We move all terms containing x to the left, all other terms to the right

-4x+3xx2=20

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