(3x*3x)+(4x*4x)=93025

Solution for (3x*3x)+(4x*4x)=93025 equation:

(3x*3x)+(4x*4x)=93025

We move all terms to the left:

(3x*3x)+(4x*4x)-(93025)=0

We add all the numbers together, and all the variables

(+3x*3x)+(+4x*4x)-93025=0

We get rid of parentheses

3x*3x+4x*4x-93025=0

Wy multiply elements

9x^2+16x^2-93025=0

We add all the numbers together, and all the variables

25x^2-93025=0

a = 25; b = 0; c = -93025;
Δ = b2-4ac
Δ = 02-4·25·(-93025)
Δ = 9302500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9302500}=3050$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3050}{2*25}=\frac{-3050}{50}
=-61
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3050}{2*25}=\frac{3050}{50}
=61
$