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(3x*3x)-(x+1x+1)=6
We move all terms to the left:
(3x*3x)-(x+1x+1)-(6)=0
We add all the numbers together, and all the variables
(+3x*3x)-(2x+1)-6=0
We get rid of parentheses
3x*3x-2x-1-6=0
We add all the numbers together, and all the variables
-2x+3x*3x-7=0
Wy multiply elements
9x^2-2x-7=0
a = 9; b = -2; c = -7;
Δ = b2-4ac
Δ = -22-4·9·(-7)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-16}{2*9}=\frac{-14}{18} =-7/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+16}{2*9}=\frac{18}{18} =1 $
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