(3x*3x)-(x+1*x+1)=6

Solution for (3x*3x)-(x+1*x+1)=6 equation:

(3x*3x)-(x+1x+1)=6

We move all terms to the left:

(3x*3x)-(x+1x+1)-(6)=0

We add all the numbers together, and all the variables

(+3x*3x)-(2x+1)-6=0

We get rid of parentheses

3x*3x-2x-1-6=0

We add all the numbers together, and all the variables

-2x+3x*3x-7=0

Wy multiply elements

9x^2-2x-7=0

a = 9; b = -2; c = -7;
Δ = b2-4ac
Δ = -22-4·9·(-7)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-16}{2*9}=\frac{-14}{18}
=-7/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+16}{2*9}=\frac{18}{18}
=1
$