(3x*4x)+8=100

Solution for (3x*4x)+8=100 equation:

(3x*4x)+8=100

We move all terms to the left:

(3x*4x)+8-(100)=0

We add all the numbers together, and all the variables

(+3x*4x)+8-100=0

We add all the numbers together, and all the variables

(+3x*4x)-92=0

We get rid of parentheses

3x*4x-92=0

Wy multiply elements

12x^2-92=0

a = 12; b = 0; c = -92;
Δ = b2-4ac
Δ = 02-4·12·(-92)
Δ = 4416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4416}=\sqrt{64*69}=\sqrt{64}*\sqrt{69}=8\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{69}}{2*12}=\frac{0-8\sqrt{69}}{24}
=-\frac{8\sqrt{69}}{24}
=-\frac{\sqrt{69}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{69}}{2*12}=\frac{0+8\sqrt{69}}{24}
=\frac{8\sqrt{69}}{24}
=\frac{\sqrt{69}}{3}
$