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(3x+-6)=(x+1)
We move all terms to the left:
(3x+-6)-((x+1))=0
We add all the numbers together, and all the variables
(3x-6)-((x+1))=0
We get rid of parentheses
3x-((x+1))-6=0
We calculate terms in parentheses: -((x+1)), so:We get rid of parentheses
(x+1)
We get rid of parentheses
x+1
Back to the equation:
-(x+1)
3x-x-1-6=0
We add all the numbers together, and all the variables
2x-7=0
We move all terms containing x to the left, all other terms to the right
2x=7
x=7/2
x=3+1/2
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