(3x+1)(24x+3)=0

Solution for (3x+1)(24x+3)=0 equation:

(3x+1)(24x+3)=0

We multiply parentheses ..

(+72x^2+9x+24x+3)=0

We get rid of parentheses

72x^2+9x+24x+3=0

We add all the numbers together, and all the variables

72x^2+33x+3=0

a = 72; b = 33; c = +3;
Δ = b2-4ac
Δ = 332-4·72·3
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-15}{2*72}=\frac{-48}{144}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+15}{2*72}=\frac{-18}{144}
=-1/8
$