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(3x+1)(2x+10)=180
We move all terms to the left:
(3x+1)(2x+10)-(180)=0
We multiply parentheses ..
(+6x^2+30x+2x+10)-180=0
We get rid of parentheses
6x^2+30x+2x+10-180=0
We add all the numbers together, and all the variables
6x^2+32x-170=0
a = 6; b = 32; c = -170;
Δ = b2-4ac
Δ = 322-4·6·(-170)
Δ = 5104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5104}=\sqrt{16*319}=\sqrt{16}*\sqrt{319}=4\sqrt{319}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-4\sqrt{319}}{2*6}=\frac{-32-4\sqrt{319}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+4\sqrt{319}}{2*6}=\frac{-32+4\sqrt{319}}{12} $
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