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(3x+1)(2x+4)=90
We move all terms to the left:
(3x+1)(2x+4)-(90)=0
We multiply parentheses ..
(+6x^2+12x+2x+4)-90=0
We get rid of parentheses
6x^2+12x+2x+4-90=0
We add all the numbers together, and all the variables
6x^2+14x-86=0
a = 6; b = 14; c = -86;
Δ = b2-4ac
Δ = 142-4·6·(-86)
Δ = 2260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2260}=\sqrt{4*565}=\sqrt{4}*\sqrt{565}=2\sqrt{565}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{565}}{2*6}=\frac{-14-2\sqrt{565}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{565}}{2*6}=\frac{-14+2\sqrt{565}}{12} $
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