(3x+1)(3x+1)(3x+1)(3x+1)=16

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Solution for (3x+1)(3x+1)(3x+1)(3x+1)=16 equation: 



(3x+1)(3x+1)(3x+1)(3x+1)=16

We move all terms to the left:

(3x+1)(3x+1)(3x+1)(3x+1)-(16)=0

We multiply parentheses ..

(+9x^2+3x+3x+1)(+9x^2+3x+3x+1)-16=0

We move all terms containing x to the left, all other terms to the right

(+9x^2+3x+3x+1)(+9x^2+3x+3x+1)=16

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