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(3x+1)(4x-13)=(2x+5)(6x-2)
We move all terms to the left:
(3x+1)(4x-13)-((2x+5)(6x-2))=0
We multiply parentheses ..
(+12x^2-39x+4x-13)-((2x+5)(6x-2))=0
We calculate terms in parentheses: -((2x+5)(6x-2)), so:We get rid of parentheses
(2x+5)(6x-2)
We multiply parentheses ..
(+12x^2-4x+30x-10)
We get rid of parentheses
12x^2-4x+30x-10
We add all the numbers together, and all the variables
12x^2+26x-10
Back to the equation:
-(12x^2+26x-10)
12x^2-12x^2-39x+4x-26x-13+10=0
We add all the numbers together, and all the variables
-61x-3=0
We move all terms containing x to the left, all other terms to the right
-61x=3
x=3/-61
x=-3/61
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