(3x+1)(x+2)=0

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Solution for (3x+1)(x+2)=0 equation:


Simplifying
(3x + 1)(x + 2) = 0

Reorder the terms:
(1 + 3x)(x + 2) = 0

Reorder the terms:
(1 + 3x)(2 + x) = 0

Multiply (1 + 3x) * (2 + x)
(1(2 + x) + 3x * (2 + x)) = 0
((2 * 1 + x * 1) + 3x * (2 + x)) = 0
((2 + 1x) + 3x * (2 + x)) = 0
(2 + 1x + (2 * 3x + x * 3x)) = 0
(2 + 1x + (6x + 3x2)) = 0

Combine like terms: 1x + 6x = 7x
(2 + 7x + 3x2) = 0

Solving
2 + 7x + 3x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(2 + x)(1 + 3x) = 0

Subproblem 1

Set the factor '(2 + x)' equal to zero and attempt to solve: Simplifying 2 + x = 0 Solving 2 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2 Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Subproblem 2

Set the factor '(1 + 3x)' equal to zero and attempt to solve: Simplifying 1 + 3x = 0 Solving 1 + 3x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 3x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 3x = 0 + -1 3x = 0 + -1 Combine like terms: 0 + -1 = -1 3x = -1 Divide each side by '3'. x = -0.3333333333 Simplifying x = -0.3333333333

Solution

x = {-2, -0.3333333333}

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