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(3x+1)(x-2)-(5x-2)(2x-1)=16-(7x+3)(x+2)
We move all terms to the left:
(3x+1)(x-2)-(5x-2)(2x-1)-(16-(7x+3)(x+2))=0
We multiply parentheses ..
(+3x^2-6x+x-2)-(5x-2)(2x-1)-(16-(7x+3)(x+2))=0
We calculate terms in parentheses: -(16-(7x+3)(x+2)), so:We get rid of parentheses
16-(7x+3)(x+2)
determiningTheFunctionDomain -(7x+3)(x+2)+16
We multiply parentheses ..
-(+7x^2+14x+3x+6)+16
We get rid of parentheses
-7x^2-14x-3x-6+16
We add all the numbers together, and all the variables
-7x^2-17x+10
Back to the equation:
-(-7x^2-17x+10)
3x^2+7x^2-6x+x+17x-(5x-2)(2x-1)-2-10=0
We multiply parentheses ..
3x^2+7x^2-(+10x^2-5x-4x+2)-6x+x+17x-2-10=0
We add all the numbers together, and all the variables
10x^2-(+10x^2-5x-4x+2)+12x-12=0
We get rid of parentheses
10x^2-10x^2+5x+4x+12x-2-12=0
We add all the numbers together, and all the variables
21x-14=0
We move all terms containing x to the left, all other terms to the right
21x=14
x=14/21
x=2/3
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