(3x+1)(x-3)=2+3(x+5

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Solution for (3x+1)(x-3)=2+3(x+5 equation: 



(3x+1)(x-3)=2+3(x+5

We move all terms to the left:

(3x+1)(x-3)-(2+3(x+5)=0

We multiply parentheses ..

(+3x^2-9x+x-3)-(2+3(x+5)=0



We calculate terms in parentheses: -(2+3(x+5), so:

2+3(x+5

determiningTheFunctionDomain
3(x+5+2

Back to the equation:

-(3(x+5+2)



We add all the numbers together, and all the variables

(+3x^2-9x+x-3)-(3(x+7)=0

We get rid of parentheses

3x^2-9x+x-(3(x+7)-3=0

We add all the numbers together, and all the variables

3x^2-8x-(3(x+7)-3=0

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