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(3x+1)(x-6)=3x^2
We move all terms to the left:
(3x+1)(x-6)-(3x^2)=0
determiningTheFunctionDomain -3x^2+(3x+1)(x-6)=0
We multiply parentheses ..
-3x^2+(+3x^2-18x+x-6)=0
We get rid of parentheses
-3x^2+3x^2-18x+x-6=0
We add all the numbers together, and all the variables
-17x-6=0
We move all terms containing x to the left, all other terms to the right
-17x=6
x=6/-17
x=-6/17
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