(3x+1)*(2x+6)=0

Solution for (3x+1)*(2x+6)=0 equation:

(3x+1)(2x+6)=0

We multiply parentheses ..

(+6x^2+18x+2x+6)=0

We get rid of parentheses

6x^2+18x+2x+6=0

We add all the numbers together, and all the variables

6x^2+20x+6=0

a = 6; b = 20; c = +6;
Δ = b2-4ac
Δ = 202-4·6·6
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-16}{2*6}=\frac{-36}{12}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+16}{2*6}=\frac{-4}{12}
=-1/3
$