(3x+1)+(2x+1)+(x+4)=46

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Solution for (3x+1)+(2x+1)+(x+4)=46 equation: 



(3x+1)+(2x+1)+(x+4)=46

We move all terms to the left:

(3x+1)+(2x+1)+(x+4)-(46)=0

We get rid of parentheses

3x+2x+x+1+1+4-46=0

We add all the numbers together, and all the variables

6x-40=0

We move all terms containing x to the left, all other terms to the right

6x=40

x=40/6

x=6+2/3

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