(3x+1)+(3x+1)+(2x+6)=36

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Solution for (3x+1)+(3x+1)+(2x+6)=36 equation: 


Simplifying
(3x + 1) + (3x + 1) + (2x + 6) = 36

Reorder the terms:
(1 + 3x) + (3x + 1) + (2x + 6) = 36

Remove parenthesis around (1 + 3x)
1 + 3x + (3x + 1) + (2x + 6) = 36

Reorder the terms:
1 + 3x + (1 + 3x) + (2x + 6) = 36

Remove parenthesis around (1 + 3x)
1 + 3x + 1 + 3x + (2x + 6) = 36

Reorder the terms:
1 + 3x + 1 + 3x + (6 + 2x) = 36

Remove parenthesis around (6 + 2x)
1 + 3x + 1 + 3x + 6 + 2x = 36

Reorder the terms:
1 + 1 + 6 + 3x + 3x + 2x = 36

Combine like terms: 1 + 1 = 2
2 + 6 + 3x + 3x + 2x = 36

Combine like terms: 2 + 6 = 8
8 + 3x + 3x + 2x = 36

Combine like terms: 3x + 3x = 6x
8 + 6x + 2x = 36

Combine like terms: 6x + 2x = 8x
8 + 8x = 36

Solving
8 + 8x = 36

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 8x = 36 + -8

Combine like terms: 8 + -8 = 0
0 + 8x = 36 + -8
8x = 36 + -8

Combine like terms: 36 + -8 = 28
8x = 28

Divide each side by '8'.
x = 3.5

Simplifying
x = 3.5

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