(3x+1)+(3x+3)=46

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Solution for (3x+1)+(3x+3)=46 equation: 



(3x+1)+(3x+3)=46

We move all terms to the left:

(3x+1)+(3x+3)-(46)=0

We get rid of parentheses

3x+3x+1+3-46=0

We add all the numbers together, and all the variables

6x-42=0

We move all terms containing x to the left, all other terms to the right

6x=42

x=42/6

x=7

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