(3x+1)+(4x-2)=

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Solution for (3x+1)+(4x-2)= equation:


Simplifying
(3x + 1) + (4x + -2) = 0

Reorder the terms:
(1 + 3x) + (4x + -2) = 0

Remove parenthesis around (1 + 3x)
1 + 3x + (4x + -2) = 0

Reorder the terms:
1 + 3x + (-2 + 4x) = 0

Remove parenthesis around (-2 + 4x)
1 + 3x + -2 + 4x = 0

Reorder the terms:
1 + -2 + 3x + 4x = 0

Combine like terms: 1 + -2 = -1
-1 + 3x + 4x = 0

Combine like terms: 3x + 4x = 7x
-1 + 7x = 0

Solving
-1 + 7x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 7x = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 7x = 0 + 1
7x = 0 + 1

Combine like terms: 0 + 1 = 1
7x = 1

Divide each side by '7'.
x = 0.1428571429

Simplifying
x = 0.1428571429

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