(3x+1)+(x+2)2=65

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Solution for (3x+1)+(x+2)2=65 equation: 



(3x+1)+(x+2)2=65

We move all terms to the left:

(3x+1)+(x+2)2-(65)=0

We multiply parentheses

(3x+1)+2x+4-65=0

We get rid of parentheses

3x+2x+1+4-65=0

We add all the numbers together, and all the variables

5x-60=0

We move all terms containing x to the left, all other terms to the right

5x=60

x=60/5

x=12

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