(3x+1)/(4)=(2x+10)/(5)

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Solution for (3x+1)/(4)=(2x+10)/(5) equation: 



(3x+1)/(4)=(2x+10)/(5)

We move all terms to the left:

(3x+1)/(4)-((2x+10)/(5))=0

We calculate fractions


3x/()+(-((2x+10)*4)/()=0



We calculate terms in parentheses: +(-((2x+10)*4)/(), so:

-((2x+10)*4)/(

We multiply all the terms by the denominator


-((2x+10)*4)



We calculate terms in parentheses: -((2x+10)*4), so:

(2x+10)*4

We multiply parentheses

8x+40

Back to the equation:

-(8x+40)



We get rid of parentheses

-8x-40

Back to the equation:

+(-8x-40)



We get rid of parentheses

3x/()-8x-40=0

We multiply all the terms by the denominator


3x-8x*()-40*()=0

We add all the numbers together, and all the variables

3x-8x*()=0

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