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(3x+1)/(5x-2)=3
We move all terms to the left:
(3x+1)/(5x-2)-(3)=0
Domain of the equation: (5x-2)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
5x!=2
x!=2/5
x!=2/5
x∈R
(3x+1)-3*(5x-2)=0
We multiply parentheses
(3x+1)-15x+6=0
We get rid of parentheses
3x-15x+1+6=0
We add all the numbers together, and all the variables
-12x+7=0
We move all terms containing x to the left, all other terms to the right
-12x=-7
x=-7/-12
x=7/12
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