(3x+1)/(6-2x)=3

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Solution for (3x+1)/(6-2x)=3 equation: 



(3x+1)/(6-2x)=3

We move all terms to the left:

(3x+1)/(6-2x)-(3)=0



Domain of the equation: (6-2x)!=0

We move all terms containing x to the left, all other terms to the right

-2x!=-6

x!=-6/-2

x!=+3

x∈R



We add all the numbers together, and all the variables

(3x+1)/(-2x+6)-3=0

We multiply all the terms by the denominator


(3x+1)-3*(-2x+6)=0

We multiply parentheses

(3x+1)+6x-18=0

We get rid of parentheses

3x+6x+1-18=0

We add all the numbers together, and all the variables

9x-17=0

We move all terms containing x to the left, all other terms to the right

9x=17

x=17/9

x=1+8/9

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