(3x+1)/(6x-2)=(2x+5)/(4x-13)

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Solution for (3x+1)/(6x-2)=(2x+5)/(4x-13) equation:


D( x )

4*x-13 = 0

6*x-2 = 0

4*x-13 = 0

4*x-13 = 0

4*x-13 = 0 // + 13

4*x = 13 // : 4

x = 13/4

6*x-2 = 0

6*x-2 = 0

6*x-2 = 0 // + 2

6*x = 2 // : 6

x = 2/6

x = 1/3

x in (-oo:1/3) U (1/3:13/4) U (13/4:+oo)

(3*x+1)/(6*x-2) = (2*x+5)/(4*x-13) // - (2*x+5)/(4*x-13)

(3*x+1)/(6*x-2)-((2*x+5)/(4*x-13)) = 0

(3*x+1)/(6*x-2)+(-1*(2*x+5))/(4*x-13) = 0

((3*x+1)*(4*x-13))/((6*x-2)*(4*x-13))+(-1*(2*x+5)*(6*x-2))/((6*x-2)*(4*x-13)) = 0

(3*x+1)*(4*x-13)-1*(2*x+5)*(6*x-2) = 0

-61*x-3 = 0

(-61*x-3)/((6*x-2)*(4*x-13)) = 0

(-61*x-3)/((6*x-2)*(4*x-13)) = 0 // * (6*x-2)*(4*x-13)

-61*x-3 = 0

-61*x-3 = 0 // + 3

-61*x = 3 // : -61

x = 3/(-61)

x = -3/61

x = -3/61

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