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(3x+1)/(x+4)=5
We move all terms to the left:
(3x+1)/(x+4)-(5)=0
Domain of the equation: (x+4)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=-4
x∈R
(3x+1)-5*(x+4)=0
We multiply parentheses
(3x+1)-5x-20=0
We get rid of parentheses
3x-5x+1-20=0
We add all the numbers together, and all the variables
-2x-19=0
We move all terms containing x to the left, all other terms to the right
-2x=19
x=19/-2
x=-9+1/2
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