(3x+1)/(x-4)=4

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Solution for (3x+1)/(x-4)=4 equation: 


D( x )

x-4 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:4) U (4:+oo)

(3*x+1)/(x-4) = 4 // - 4

(3*x+1)/(x-4)-4 = 0

(3*x+1)/(x-4)+(-4*(x-4))/(x-4) = 0

3*x-4*(x-4)+1 = 0

17-x = 0

(17-x)/(x-4) = 0

(17-x)/(x-4) = 0 // * x-4

17-x = 0

17-x = 0 // - 17

-x = -17 // * -1

x = 17

x = 17

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