(3x+1)/2+(2x+1)/3=x/2+5/3

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Solution for (3x+1)/2+(2x+1)/3=x/2+5/3 equation: 


x in (-oo:+oo)

(3*x+1)/2+(2*x+1)/3 = x/2+5/3 // - x/2+5/3

(3*x+1)/2+(2*x+1)/3-(x/2)-(5/3) = 0

(3*x+1)/2+(2*x+1)/3-(x/2)-5/3 = 0

(3*x+1)/2+(2*x+1)/3-x/2-5/3 = 0

(3*(3*x+1))/(2*3)+(2*(2*x+1))/(2*3)+(3*(-x))/(2*3)+(-5*2)/(2*3) = 0

3*(3*x+1)+2*(2*x+1)+3*(-x)-5*2 = 0

13*x-3*x-10+5 = 0

10*x-10+5 = 0

10*x-5 = 0

(10*x-5)/(2*3) = 0

(10*x-5)/(2*3) = 0 // * 2*3

10*x-5 = 0

10*x-5 = 0 // + 5

10*x = 5 // : 10

x = 5/10

x = 1/2

x = 1/2

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