(3x+1)/2=(4x+6)/5

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Solution for (3x+1)/2=(4x+6)/5 equation: 



(3x+1)/2=(4x+6)/5

We move all terms to the left:

(3x+1)/2-((4x+6)/5)=0

We calculate fractions


3x/()+(-((4x+6)*2)/()=0



We calculate terms in parentheses: +(-((4x+6)*2)/(), so:

-((4x+6)*2)/(

We multiply all the terms by the denominator


-((4x+6)*2)



We calculate terms in parentheses: -((4x+6)*2), so:

(4x+6)*2

We multiply parentheses

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

-8x-12

Back to the equation:

+(-8x-12)



We get rid of parentheses

3x/()-8x-12=0

We multiply all the terms by the denominator


3x-8x*()-12*()=0

We add all the numbers together, and all the variables

3x-8x*()=0

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