(3x+1)/2=-16

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Solution for (3x+1)/2=-16 equation: 



(3x+1)/2=-16

We move all terms to the left:

(3x+1)/2-(-16)=0

We add all the numbers together, and all the variables

(3x+1)/2+16=0

We multiply all the terms by the denominator


(3x+1)+16*2=0

We add all the numbers together, and all the variables

(3x+1)+32=0

We get rid of parentheses

3x+1+32=0

We add all the numbers together, and all the variables

3x+33=0

We move all terms containing x to the left, all other terms to the right

3x=-33

x=-33/3

x=-11

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