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(3x+1)/2=x+1
We move all terms to the left:
(3x+1)/2-(x+1)=0
We get rid of parentheses
(3x+1)/2-x-1=0
We multiply all the terms by the denominator
(3x+1)-x*2-1*2=0
We add all the numbers together, and all the variables
(3x+1)-x*2-2=0
Wy multiply elements
(3x+1)-2x-2=0
We get rid of parentheses
3x-2x+1-2=0
We add all the numbers together, and all the variables
x-1=0
We move all terms containing x to the left, all other terms to the right
x=1
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